//求闰年数y
for (int i=2000; i<year; i++)
{
if (((i%4==0)&&(i%100!=0))||(i%400==0))
{
y++;
}
}
//分别求大月n和小月m
for (int i=1;i<month;i++)
{
switch (i)
{
case 2:
if (((year%4==0)&&(year%100!=0))||(year%400==0))
{
s++;
}
break;
case 4:
case 6:
case 9:
case 11:
m++;
break;
default:
n++;
break;
}
}
//算出总天数
count = (year-2000)*355 + y + n*31 + m*30 + s*29 + day ;