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标题: 为什么显示方法没找到? [打印本页]
作者: 15098037606 时间: 2015-4-20 16:07
标题: 为什么显示方法没找到?
#import <Foundation/Foundation.h>
@interface NSString( XZ )// 方法声明
+ (void) zifuchuanfanzhuan:(NSMutableString *)s1;
+ (int) letterCount: (NSMutableString *)s2;
+ (NSMutableString *) qukongge:(NSMutableString *)s3;
@end
@implementation NSString( XZ )// 方法实现
+ (void) zifuchuanfanzhuan:(NSMutableString *)s1
{
int changDu = (int)s1.length;
// 将字符串最右端字符的下标储存在i中,遍历,直到字符串中间位置结束
for (int i = (changDu - 1); i >= (changDu / 2); i--)
{
// 在遍历的同时储存要交换的两个字符的值
char right = [s1 characterAtIndex:i];
char left = [s1 characterAtIndex:(changDu - i - 1)];
// 交换两个字符的值,同时将两个字符转换成字符串,方便后面的替换字符串操作
NSString *rightNow = [[NSString alloc] initWithFormat:@"%c",left];
NSString *leftNow = [[NSString alloc]initWithFormat:@"%c",right];
// 将交换好的字符的字符串替换进原来的字符串中
[s1 replaceCharactersInRange:NSMakeRange(i, 1) withString:rightNow];
[s1 replaceCharactersInRange:NSMakeRange(changDu - i - 1, 1) withString:leftNow];
}
+ (int) letterCount: (NSMutableString *)s2
{
int count = 0;
for (int i=0 ;i<self.length;i++)
{
unichar c = [self characterAtIndex :i];
if(( c>='a'&& c<='z')||(c>='A'&& c<='Z'))//判断是否为英文字母
{
count++;
}
}
return count;
}
+ (NSMutableString *) qukongge:(NSString *)s3
{
NSMutableString *newS1 = [NSMutableString stringWithString:s3];
NSMutableString *temp = nil ;
for(int i =0; i < self.length; i++)
{
char c = [newS1 characterAtIndex:i]; // 获取当前位置的字符
if(c == ' ')
{
temp = [newS1 deleteCharactersInRange:NSMakeRange(i, 1)];
}
else break;
}
return temp;
}
@end
int main()
{
NSMutableString *s1 = @" 123 ";
NSMutableString *s2 = @" 5435abc54abc3AHJ5 ";
NSMutableString *s3=@" 1235 45 ";
NSMutableString *s1 = [NSString zifuchuanfanzhuan:s1]
int count = [NSString letterCount: s2] ;
NSMutableString *s3 = [NSString qukongge: s3];
NSLog(@"字符串反转后输出是%@", s1);
NSLog(@"用类方法2后,字母个数是%d", count);
NSLog(@"用类方法3去两端空格后,输出是 %@", s3);
return 0;
}
警告:method for definition 'qukongge:' not found method for definition 'letterCount:' not found 报错:use of declared identifier 'letterCount'哪位帮我修改一下?
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