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标题: Ｃ语言如何判断输入的正整数是否是整型？负数没有实现.... [打印本页]

作者: tabor 时间: 2015-6-28 14:26
标题: Ｃ语言如何判断输入的正整数是否是整型？负数没有实现....

用户从键盘上输入两个整数，然后输出

#include <stdio.h>

#include <math.h>

int main()

{

//定义两个整型变量, 2个跳转符

int num1 = 1, num2 = 1, jump=0, count =0;

long long sum = 0;

//开始输入

for(int j=0; j<2; j++)

{

//iuput char

{

//提示范围，并开始输入第n个数据

printf("%lld\n",INT64_MAX);

printf("Please input num%d:",j+1);

//初始化存储区

char a[2][30]=

{

{'0','0','0','0','0','0','0','0','0','0','0','0','0','0','0','0','0','0','0','0','0','0','0','0','0','0','0','0','0','0'},

{'0','0','0','0','0','0','0','0','0','0','0','0','0','0','0','0','0','0','0','0','0','0','0','0','0','0','0','0','0','0'}

};

rewind(stdin);

count = 0;

jump = 0;

//开始输入数据，并一次将用户放入缓存的数据全部收取

for (int i=0; i<30; i++)

{

scanf("%c",&a[j]);

// a[j]=getchar();

printf("i = %d,a[%d][%d] = %c = \'\\%d\'\n",i,j,i,a[j],a[j]);

//回车后数据固定下来

if(a[j] == 10)

{

//提示输入的数据，是否符合要求

printf("亲，你一共输入了%d位数据！\n",i);

a[j]='0';

count = i;

//数据重置开始

for(int k=0; k<i; k++)

{

//已经输入的数据移到低位

a[j][29-k] = a[j][i-k-1];

//将移出位置0

a[j][i-k-1] = '0';

}

//退出赋值进程

i = 30;

sum = 0;

作者: tabor 时间: 2015-6-28 14:27

                  //当前字符串
                  printf("当前输入a[%d] = %s\n",j,a[j]);

                  //转换成正常的数据
                  for( int temp=0; temp<30;temp++)
                  {
                     a[j][temp] -= 48;
                     printf("转换后：\n");
                     printf("i = %d, a[%d][%d] = %d,%lld\n",temp,j,temp,a[j][temp],sum);
                     sum +=(long long)(a[j][temp]*(long long)pow(10,29-temp));
                  }
                  printf("sum = %010lld, count = %d\n",sum,count);
                  switch(count/10)
                  {
                     case 2 :
                        printf("你现在总共输入%d位，严重超范围！\n",count);
                        jump = 30;
                        printf("%d\n",jump-30);
                        break;
                     case 1:
                        printf("你现在总共输入%d位，超范围了！\n",count);
                        jump = 30;
                        printf("%d\n", jump - 30);
                        break;
                        //只有这时，才是正常的输入，并进行重置
                     case 0:
                        //提示是正常的
                        printf("范围正常，可以得到正常的输出！\n");

                        break;
                     default:
                        jump = 30;
                        printf("这样是不行的，输入的太大，都%d了！\n",count);
                        break;
                  }
            }
         }

         //num大于整型最大同时位数不大于10
      }while(sum > INT32_MAX || jump == 30);
      if(j==0)
      {
         num1 = (int)sum;
         printf("%010d\n",num1);
      }

      if(j==1)
      {
         num2 = (int)sum;
         printf("%010d\n", num2);
      }
}

//output
printf("num1 = %d, num2 = %d \n",num1,num2);
return 0;
}

作者: tabor 时间: 2015-6-28 14:29
怎么才能整个代码一次贴出来啊
作者: 18678927239 时间: 2015-6-28 15:41
没看懂  = =  mark 求大神指教
作者: XiaoBaoMi 时间: 2015-6-28 15:44
楼主说的不错学习了
作者: tabor 时间: 2015-6-28 16:02
9223372036854775807
Please input num1:357493275942759274536546
i = 0,a[0][0] = 3 = '\51'
i = 1,a[0][1] = 5 = '\53'
i = 2,a[0][2] = 7 = '\55'
i = 3,a[0][3] = 4 = '\52'
i = 4,a[0][4] = 9 = '\57'
i = 5,a[0][5] = 3 = '\51'
i = 6,a[0][6] = 2 = '\50'
i = 7,a[0][7] = 7 = '\55'
i = 8,a[0][8] = 5 = '\53'
i = 9,a[0][9] = 9 = '\57'
i = 10,a[0][10] = 4 = '\52'
i = 11,a[0][11] = 2 = '\50'
i = 12,a[0][12] = 7 = '\55'
i = 13,a[0][13] = 5 = '\53'
i = 14,a[0][14] = 9 = '\57'
i = 15,a[0][15] = 2 = '\50'
i = 16,a[0][16] = 7 = '\55'
i = 17,a[0][17] = 4 = '\52'
i = 18,a[0][18] = 5 = '\53'
i = 19,a[0][19] = 3 = '\51'
i = 20,a[0][20] = 6 = '\54'
i = 21,a[0][21] = 5 = '\53'
i = 22,a[0][22] = 4 = '\52'
i = 23,a[0][23] = 6 = '\54'
i = 24,a[0][24] =
= '\10'
亲，你一共输入了24位数据！
当前输入a[0] = 000000357493275942759274536546000000000000000000000000000000
转换后：
i = 0, a[0][0] = 0,0
转换后：
i = 1, a[0][1] = 0,0
转换后：
i = 2, a[0][2] = 0,0
转换后：
i = 3, a[0][3] = 0,0
转换后：
i = 4, a[0][4] = 0,0
转换后：
i = 5, a[0][5] = 0,0
转换后：
i = 6, a[0][6] = 3,0
转换后：
i = 7, a[0][7] = 5,-9223372036854775808
转换后：
i = 8, a[0][8] = 7,0
转换后：
i = 9, a[0][9] = 4,-9223372036854775808
转换后：
i = 10, a[0][10] = 9,-9223372036854775808
转换后：
i = 11, a[0][11] = 3,0
转换后：
i = 12, a[0][12] = 2,3000000000000000000
转换后：
i = 13, a[0][13] = 7,3200000000000000000
转换后：
i = 14, a[0][14] = 5,3270000000000000000
转换后：
i = 15, a[0][15] = 9,3275000000000000000
转换后：
i = 16, a[0][16] = 4,3275900000000000000
转换后：
i = 17, a[0][17] = 2,3275940000000000000
转换后：
i = 18, a[0][18] = 7,3275942000000000000
转换后：
i = 19, a[0][19] = 5,3275942700000000000
转换后：
i = 20, a[0][20] = 9,3275942750000000000
转换后：
i = 21, a[0][21] = 2,3275942759000000000
转换后：
i = 22, a[0][22] = 7,3275942759200000000
转换后：
i = 23, a[0][23] = 4,3275942759270000000
转换后：
i = 24, a[0][24] = 5,3275942759274000000
转换后：
i = 25, a[0][25] = 3,3275942759274500000
转换后：
i = 26, a[0][26] = 6,3275942759274530000
转换后：
i = 27, a[0][27] = 5,3275942759274536000
转换后：
i = 28, a[0][28] = 4,3275942759274536500
转换后：
i = 29, a[0][29] = 6,3275942759274536540
sum = 3275942759274536546, count = 24
你现在总共输入24位，严重超范围！
0
9223372036854775807
Please input num1:345
i = 0,a[0][0] = 3 = '\51'
i = 1,a[0][1] = 4 = '\52'
i = 2,a[0][2] = 5 = '\53'
i = 3,a[0][3] =
= '\10'
亲，你一共输入了3位数据！
当前输入a[0] = 000000000000000000000000000345000000000000000000000000000000
转换后：
i = 0, a[0][0] = 0,0
转换后：
i = 1, a[0][1] = 0,0
转换后：
i = 2, a[0][2] = 0,0
转换后：
i = 3, a[0][3] = 0,0
转换后：
i = 4, a[0][4] = 0,0
转换后：
i = 5, a[0][5] = 0,0
转换后：
i = 6, a[0][6] = 0,0
转换后：
i = 7, a[0][7] = 0,0
转换后：
i = 8, a[0][8] = 0,0
转换后：
i = 9, a[0][9] = 0,0
转换后：
i = 10, a[0][10] = 0,0
转换后：
i = 11, a[0][11] = 0,0
转换后：
i = 12, a[0][12] = 0,0
转换后：
i = 13, a[0][13] = 0,0
转换后：
i = 14, a[0][14] = 0,0
转换后：
i = 15, a[0][15] = 0,0
转换后：
i = 16, a[0][16] = 0,0
转换后：
i = 17, a[0][17] = 0,0
转换后：
i = 18, a[0][18] = 0,0
转换后：
i = 19, a[0][19] = 0,0
转换后：
i = 20, a[0][20] = 0,0
转换后：
i = 21, a[0][21] = 0,0
转换后：
i = 22, a[0][22] = 0,0
转换后：
i = 23, a[0][23] = 0,0
转换后：
i = 24, a[0][24] = 0,0
转换后：
i = 25, a[0][25] = 0,0
转换后：
i = 26, a[0][26] = 0,0
转换后：
i = 27, a[0][27] = 3,0
转换后：
i = 28, a[0][28] = 4,300
转换后：
i = 29, a[0][29] = 5,340
sum = 0000000345, count = 3
范围正常，可以得到正常的输出！
0000000345
9223372036854775807
Please input num2:7304523805794370243254
i = 0,a[1][0] = 7 = '\55'
i = 1,a[1][1] = 3 = '\51'
i = 2,a[1][2] = 0 = '\48'
i = 3,a[1][3] = 4 = '\52'
i = 4,a[1][4] = 5 = '\53'
i = 5,a[1][5] = 2 = '\50'
i = 6,a[1][6] = 3 = '\51'
i = 7,a[1][7] = 8 = '\56'
i = 8,a[1][8] = 0 = '\48'
i = 9,a[1][9] = 5 = '\53'
i = 10,a[1][10] = 7 = '\55'
i = 11,a[1][11] = 9 = '\57'
i = 12,a[1][12] = 4 = '\52'
i = 13,a[1][13] = 3 = '\51'
i = 14,a[1][14] = 7 = '\55'
i = 15,a[1][15] = 0 = '\48'
i = 16,a[1][16] = 2 = '\50'
i = 17,a[1][17] = 4 = '\52'
i = 18,a[1][18] = 3 = '\51'
i = 19,a[1][19] = 2 = '\50'
i = 20,a[1][20] = 5 = '\53'
i = 21,a[1][21] = 4 = '\52'
i = 22,a[1][22] =
= '\10'
亲，你一共输入了22位数据！
当前输入a[1] = 000000007304523805794370243254
转换后：
i = 0, a[1][0] = 0,0
转换后：
i = 1, a[1][1] = 0,0
转换后：
i = 2, a[1][2] = 0,0
转换后：
i = 3, a[1][3] = 0,0
转换后：
i = 4, a[1][4] = 0,0
转换后：
i = 5, a[1][5] = 0,0
转换后：
i = 6, a[1][6] = 0,0
转换后：
i = 7, a[1][7] = 0,0
转换后：
i = 8, a[1][8] = 7,0
转换后：
i = 9, a[1][9] = 3,-9223372036854775808
转换后：
i = 10, a[1][10] = 0,0
转换后：
i = 11, a[1][11] = 4,0
转换后：
i = 12, a[1][12] = 5,4000000000000000000
转换后：
i = 13, a[1][13] = 2,4500000000000000000
转换后：
i = 14, a[1][14] = 3,4520000000000000000
转换后：
i = 15, a[1][15] = 8,4523000000000000000
转换后：
i = 16, a[1][16] = 0,4523800000000000000
转换后：
i = 17, a[1][17] = 5,4523800000000000000
转换后：
i = 18, a[1][18] = 7,4523805000000000000
转换后：
i = 19, a[1][19] = 9,4523805700000000000
转换后：
i = 20, a[1][20] = 4,4523805790000000000
转换后：
i = 21, a[1][21] = 3,4523805794000000000
转换后：
i = 22, a[1][22] = 7,4523805794300000000
转换后：
i = 23, a[1][23] = 0,4523805794370000000
转换后：
i = 24, a[1][24] = 2,4523805794370000000
转换后：
i = 25, a[1][25] = 4,4523805794370200000
转换后：
i = 26, a[1][26] = 3,4523805794370240000
转换后：
i = 27, a[1][27] = 2,4523805794370243000
转换后：
i = 28, a[1][28] = 5,4523805794370243200
转换后：
i = 29, a[1][29] = 4,4523805794370243250
sum = 4523805794370243254, count = 22
你现在总共输入22位，严重超范围！
0
9223372036854775807
Please input num2:456
i = 0,a[1][0] = 4 = '\52'
i = 1,a[1][1] = 5 = '\53'
i = 2,a[1][2] = 6 = '\54'
i = 3,a[1][3] =
= '\10'
亲，你一共输入了3位数据！
当前输入a[1] = 000000000000000000000000000456
转换后：
i = 0, a[1][0] = 0,0
转换后：
i = 1, a[1][1] = 0,0
转换后：
i = 2, a[1][2] = 0,0
转换后：
i = 3, a[1][3] = 0,0
转换后：
i = 4, a[1][4] = 0,0
转换后：
i = 5, a[1][5] = 0,0
转换后：
i = 6, a[1][6] = 0,0
转换后：
i = 7, a[1][7] = 0,0
转换后：
i = 8, a[1][8] = 0,0
转换后：
i = 9, a[1][9] = 0,0
转换后：
i = 10, a[1][10] = 0,0
转换后：
i = 11, a[1][11] = 0,0
转换后：
i = 12, a[1][12] = 0,0
转换后：
i = 13, a[1][13] = 0,0
转换后：
i = 14, a[1][14] = 0,0
转换后：
i = 15, a[1][15] = 0,0
转换后：
i = 16, a[1][16] = 0,0
转换后：
i = 17, a[1][17] = 0,0
转换后：
i = 18, a[1][18] = 0,0
转换后：
i = 19, a[1][19] = 0,0
转换后：
i = 20, a[1][20] = 0,0
转换后：
i = 21, a[1][21] = 0,0
转换后：
i = 22, a[1][22] = 0,0
转换后：
i = 23, a[1][23] = 0,0
转换后：
i = 24, a[1][24] = 0,0
转换后：
i = 25, a[1][25] = 0,0
转换后：
i = 26, a[1][26] = 0,0
转换后：
i = 27, a[1][27] = 4,0
转换后：
i = 28, a[1][28] = 5,400
转换后：
i = 29, a[1][29] = 6,450
sum = 0000000456, count = 3
范围正常，可以得到正常的输出！
0000000456
num1 = 345, num2 = 456

上面是输入信息〜〜

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