,这同样会出问题
作者: neverbloom7 时间: 2015-8-9 00:26
就是这么绕的~~~
int *arr[2];
int a=1,b=2;
int *p1=&a,*p2=&b;
arr[0]=p1,arr[1]=p2;
int *tmp=p1;//int *tmp=&a;
printf("*tmp=%d,~~~*tmp的地址是:%p\n",*tmp,tmp);
分开写能好理解一些,
int *arr[2];
int a=1,b=2;
int *p1,*p2;
p1=&a,p1=&a;
arr[0]=p1,arr[1]=p2;
int *tmp=p1;//int *tmp=&a;
printf("*tmp=%d,~~~*tmp的地址是:%p\n",*tmp,tmp);
作者: neverbloom7 时间: 2015-8-9 00:31
printf("*arr[0]的地址是:%p~~~arr的地址是:%p\n",&arr[0],arr);//它们是一样的
作者: nancexp 时间: 2015-8-9 15:48
刚刚讲得,也是有点绕
作者: 阿伦666 时间: 2015-8-9 16:26
其实,数组指针就是指针,指针数组就是数组,里面存了一堆地址,
#include <stdio.h>
int main()
{
//定义指针数组
int a = 1,b = 2, c = 3;
int *pa = &a;
int *pb = &b;
int *pc = &c;
int *arr[3] = {pa,pb,pc};
for (int i = 0; i < 3; i++) {
printf("*arr[%d] = %p\n",i, &arr);
}
//定义数组指针
int arr1[3] = {1,2,3};
int (*p)[3] = &arr1;
*p[0] = 4;
for (int i = 0; i < 3; i++) {
printf("*arr1[%d] = %d\n",i, arr1);
}
//定义数组元素指针
int arr2[3] = {1,2,3};
int *parr20 = &arr2[0];
int *parr21 = &arr2[1];
int *parr22 = &arr2[2];
*parr20 = 5;
*parr21 = 5;
*parr22 = 5;
for (int i = 0; i < 3; i++) {
printf("*arr2[%d] = %d\n",i, arr2);
}
return 0;
}
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