标题: c语言基础算法案例 [打印本页] 作者: 唐阿丽 时间: 2015-11-12 11:12 标题: c语言基础算法案例 很适合刚开始学C语言的同学。
1、C语言打印一条语句
源代码：
/* C Program to print a sentence. */
#include <stdio.h>
int main()
{
printf("C Programming"); /* printf() prints the content inside quotation */
return 0;
}
输出：
C Programming
2、C语言打印用户输入的一个整数
源代码：
#include <stdio.h>
int main()
{
int num;
printf("Enter a integer: ");
scanf("%d",&num); /* Storing a integer entered by user in variable num */
printf("You entered: %d",num);
return 0;
}
输出：
Enter a integer: 25
You entered: 25
3、C语言实现两个整数相加
源代码：
/*C programming source code to add and display the sum of two integers entered by user */
#include <stdio.h>
int main( )
{
int num1, num2, sum;
printf("Enter two integers: ");
scanf("%d %d",&num1,&num2); /* Stores the two integer entered by user in variable num1 and num2 */
sum=num1+num2; /* Performs addition and stores it in variable sum */
printf("Sum: %d",sum); /* Displays sum */
return 0;
}
输出：
Enter two integers: 12
11
Sum: 23
4、C语言实现两个小数相乘
源代码：
/*C program to multiply and display the product of two floating point numbers entered by user. */
#include <stdio.h>
int main( )
{
float num1, num2, product;
printf("Enter two numbers: ");
scanf("%f %f",&num1,&num2); /* Stores the two floating point numbers entered by user in variable num1 and num2 respectively */
product = num1*num2; /* Performs multiplication and stores it */
printf("Product: %f",product);
return 0;
}
输出：
Enter two numbers: 2.4
1.1
Product: 2.640000
5、C语言查找字符的ASCII值
源代码：
/* Source code to find ASCII value of a character entered by user */
#include <stdio.h>
int main(){
char c;
printf("Enter a character: ");
scanf("%c",&c); /* Takes a character from user */
printf("ASCII value of %c = %d",c,c);
return 0;
}
输出：
Enter a character: G
ASCII value of G = 71
6、C语言根据用户输入的整数做商和余数
源代码：
/* C Program to compute remainder and quotient */
基本语法是：
temp = sizeof(operand);
/* Here, temp is a variable of type integer,i.e, sizeof() operator
returns integer value. */
源代码：
/* This program computes the size of variable using sizeof operator.*/
#include <stdio.h>
int main(){
int a;
float b;
double c;
char d;
printf("Size of int: %d bytes\n",sizeof(a));
printf("Size of float: %d bytes\n",sizeof(b));
printf("Size of double: %d bytes\n",sizeof(c));
printf("Size of char: %d byte\n",sizeof(d));
return 0;
}
输出：
Size of int: 4 bytes
Size of float: 4 bytes
Size of double: 8 bytes
Size of char: 1 byte
注：可能会由于系统的不同出来的结果也不尽相同。
8、C语言获取关键字long的长度范围
源代码：
#include <stdio.h>
int main(){
int a;
long int b; /* int is optional. */
long long int c; /* int is optional. */
printf("Size of int = %d bytes\n",sizeof(a));
printf("Size of long int = %ld bytes\n",sizeof(b));
printf("Size of long long int = %ld bytes",sizeof(c));
return 0;
}
输出：
Size of int = 4 bytes
Size of long int = 4 bytes
Size of long long int = 8 bytes
9、C语言交换数值
源代码：
#include <stdio.h>
int main(){
float a, b, temp;
printf("Enter value of a: ");
scanf("%f",&a);
printf("Enter value of b: ");
scanf("%f",&b);
temp = a; /* Value of a is stored in variable temp */
a = b; /* Value of b is stored in variable a */
b = temp; /* Value of temp(which contains initial value of a) is stored in variable b*/
printf("\nAfter swapping, value of a = %.2f\n", a);
printf("After swapping, value of b = %.2f", b);
return 0;
}
输出：
Enter value of a: 1.20
Enter value of b: 2.45
After swapping, value of a = 2.45
After swapping, value of b = 1.2
10、C语言检查数值是奇数还是偶数
源代码：
/*C program to check whether a number entered by user is even or odd. */
#include <stdio.h>
int main(){
int num;
printf("Enter an integer you want to check: ");
scanf("%d",&num);
if((num%2)==0) /* Checking whether remainder is 0 or not. */
printf("%d is even.",num);
else
printf("%d is odd.",num);
return 0;
}
输出1：
Enter an integer you want to check: 25
25 is odd.
输出2：
Enter an integer you want to check: 12
12 is even.
也可以用条件运算符解决：
/* C program to check whether an integer is odd or even using conditional operator */
#include <stdio.h>
int main(){
int num;
printf("Enter an integer you want to check: ");
scanf("%d",&num);
((num%2)==0) ? printf("%d is even.",num) : printf("%d is odd.",num);
return 0;
}
11、C语言检查是元音还是辅音
源代码：
#include <stdio.h>
int main(){
char c;
printf("Enter an alphabet: ");
scanf("%c",&c);
if(c=='a'||c=='A'||c=='e'||c=='E'||c=='i'||c=='I'||c=='o'||c=='O'||c=='u'||c=='U')
printf("%c is a vowel.",c);
else
printf("%c is a consonant.",c);
return 0;
}
输出1：
Enter an alphabet: i
i is a vowel.
输出2：
Enter an alphabet: G
G is a consonant.
也可以用条件运算符解决
/* C program to check whether a character is vowel or consonant using conditional operator */
#include <stdio.h>
int main(){
char c;
printf("Enter an alphabet: ");
scanf("%c",&c);
(c=='a'||c=='A'||c=='e'||c=='E'||c=='i'||c=='I'||c=='o'||c=='O'||c=='u'||c=='U') ? printf("%c is a vowel.",c) : printf("%c is a consonant.",c);
return 0;
}
输出结果和上面的程序相同。
12、C语言实现从三个数值中查找最大值
实现1：
/* C program to find largest number using if statement only */
#include <stdio.h>
int main(){
float a, b, c;
printf("Enter three numbers: ");
scanf("%f %f %f", &a, &b, &c);
if(a>=b && a>=c)
printf("Largest number = %.2f", a);
if(b>=a && b>=c)
printf("Largest number = %.2f", b);
if(c>=a && c>=b)
printf("Largest number = %.2f", c);
return 0;
}
实现2：
/* C program to find largest number using if...else statement */
#include <stdio.h>
int main(){
float a, b, c;
printf("Enter three numbers: ");
scanf("%f %f %f", &a, &b, &c);
if (a>=b)
{
if(a>=c)
printf("Largest number = %.2f",a);
else
printf("Largest number = %.2f",c);
}
else
{
if(b>=c)
printf("Largest number = %.2f",b);
else
printf("Largest number = %.2f",c);
}
return 0;
}
实现3：
/* C Program to find largest number using nested if...else statement */
#include <stdio.h>
int main(){
float a, b, c;
printf("Enter three numbers: ");
scanf("%f %f %f", &a, &b, &c);
if(a>=b && a>=c)
printf("Largest number = %.2f", a);
else if(b>=a && b>=c)
printf("Largest number = %.2f", b);
else
printf("Largest number = %.2f", c);
return 0;
}
输出结果相同：
Enter three numbers: 12.2
13.452
10.193
Largest number = 13.45
13、C语言解一元二次方程
源代码：
/* Program to find roots of a quadratic equation when coefficients are entered by user. */
/* Library function sqrt() computes the square root. */
#include <stdio.h>
#include <math.h> /* This is needed to use sqrt() function.*/
int main()
{
float a, b, c, determinant, r1,r2, real, imag;
printf("Enter coefficients a, b and c: ");
scanf("%f%f%f",&a,&b,&c);
determinant=b*b-4*a*c;
if (determinant>0)
{
r1= (-b+sqrt(determinant))/(2*a);
r2= (-b-sqrt(determinant))/(2*a);
printf("Roots are: %.2f and %.2f",r1 , r2);
}
else if (determinant==0)
{
r1 = r2 = -b/(2*a);
printf("Roots are: %.2f and %.2f", r1, r2);
}
else
{
real= -b/(2*a);
imag = sqrt(-determinant)/(2*a);
printf("Roots are: %.2f+%.2fi and %.2f-%.2fi", real, imag, real, imag);
}
return 0;
}
输出1：
Enter coefficients a, b and c: 2.3
4
5.6
Roots are: -0.87+1.30i and -0.87-1.30i
输出2：
Enter coefficients a, b and c: 4
1
0
Roots are: 0.00 and -0.25 作者: acdd112 时间: 2015-11-12 13:12
楼主辛苦 支持一下作者: cbl16888 时间: 2015-11-12 22:17
来取经了，谢谢作者: 陌忆 时间: 2015-11-12 22:37
感觉没什么用啊作者: cc_2436 时间: 2015-11-12 22:41
楼主码字也不容易 支持下作者: heima73924130 时间: 2015-11-12 22:44
赞一个！！！！！！作者: liuchuan_alex 时间: 2015-11-12 22:53
纯英文,表示很牛C作者: 18537947462 时间: 2015-11-13 22:13
先顶一下，再看作者: 沐小妖mavs 时间: 2015-11-13 23:02
谢谢啦 先收藏起来作者: 能不能行 时间: 2015-11-14 22:16
如果楼主是手敲的代码那就厉害了.这键盘得敲一会