标题: Java语言基础 [打印本页] 作者: wxw_0818 时间: 2016-5-5 01:01 标题: Java语言基础 Java语言基础
* A:案例演示
* 请分别计算出a,b,c的值?
*
int a = 10;
int b = 10;
int c = 10;
a = b++;
c = --a;
b = ++a;
a = c--;
* B:案例演示
* 请分别计算出x,y的值?
int x = 4;
int y = (x++)+(++x)+(x*10);
* C:面试题
* byte b = 10;
* b++;
* b = b + 1;
* 问哪句会报错,为什么
案例：
classTest1_Operator{
publicstaticvoid main(String[] args){
//第一题
/*int a = 10;
int b = 10;
int c = 10;
a = b++; //a = 10 ,b = 11
c = --a; //a = 9, c = 9
b = ++a; //a = 10, b = 10
a = c--; //a = 9, c = 8
System.out.println("a = " + a + ",b = " + b + ",c = " + c);*/
//第二题
/*int x = 4;
// 4 + 6+ 60
int y = (x++)+(++x)+(x*10);
System.out.println("x = " + x + ",y = " + y);*/
//第三题问哪句会报错,为什么
byte b =10;
//b++; //b = (byte)(b + 1)
b = b +1; //当byte与int进行混合运算的时候,会提升为int类型,两个int相加的结果还是int,赋值给byte会损失精度
System.out.println("b = "+ b);