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标题:
java中7种字符串反转方法
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作者:
IT_JM
时间:
2013-9-30 00:34
标题:
java中7种字符串反转方法
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<DIV class=blockcode>
<BLOCKQUOTE>import java.util.Stack;
public class StringReverse {
public static String reverse1(String s) {
int length = s.length();
if (length <= 1)
eturn s;
String left = s.substring(0, length / 2);
String right = s.substring(length / 2, length);
return reverse1(right) + reverse1(left);
}
public static String reverse2(String s) {
int length = s.length();
String reverse = "";
for (int i = 0; i < length; i++)
reverse = s.charAt(i) + reverse;
return reverse;
}
public static String reverse3(String s) {
char[] array = s.toCharArray();
String reverse = "";
for (int i = array.length - 1; i >= 0; i--)
reverse += array[i];
return reverse;
}
public static String reverse4(String s) {
return new StringBuffer(s).reverse().toString();
}
public static String reverse5(String orig) {
char[] s = orig.toCharArray();
int n = s.length - 1;
int halfLength = n / 2;
char temp = s[i];
s[i] = s[n - i];
s[n - i] = temp;
}
return new String(s);
}
public static String reverse6(String s) {
char[] str = s.toCharArray();
int begin = 0;
int end = s.length() - 1;
while (begin < end) {
str[begin] = (char) (str[begin] ^ str[end]);
str[end] = (char) (str[begin] ^ str[end]);
str[begin] = (char) (str[end] ^ str[begin]);
begin++;
end--;
}
return new String(str);
}
public static String reverse7(String s) {
char[] str = s.toCharArray();
Stack<Character> stack = new Stack<Character>();
for (int i = 0; i < str.length; i++)
stack.push(str[i]);
String reversed = "";
for (int i = 0; i < str.length; i++)
reversed += stack.pop();
return reversed;
}
}
复制代码
作者:
王清华0
时间:
2013-9-30 11:30
这么全面,赞一个。
作者:
潘才新
时间:
2013-9-30 22:43
额。我表示看不懂
作者:
hanfei2511
时间:
2013-10-4 12:57
本帖最后由 hanfei2511 于 2013-10-4 13:03 编辑
虽然第五个方法除了点错,但真的挺全,请问,那种方法效率最高呢?对了,搞个长的字符串,我都测试下,嘿嘿,受教了。
作者:
IT_JM
时间:
2013-10-5 08:19
hanfei2511 发表于 2013-10-4 12:57
虽然第五个方法除了点错,但真的挺全,请问,那种方法效率最高呢?对了,搞个长的字符串,我都测试下,嘿嘿 ...
我也是刚接触java,以前我是学c++的,共同学习,哈哈{:soso_e112:}
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