以前有人发过解答,但有些复杂看不懂。程序如下- package com.itheima;
- public class Demo10 {
- public static void main(String[] args) throws InterruptedException {
- Object obj1 = new Object();
- Object obj2 = new Object();
- Object obj3 = new Object();
- Thread t1 = new Thread(new SyncThread(obj1, obj2), "t1");
- Thread t2 = new Thread(new SyncThread(obj2, obj3), "t2");
- Thread t3 = new Thread(new SyncThread(obj3, obj1), "t3");
- t1.start();
- Thread.sleep(5000);
- t2.start();
- Thread.sleep(5000);
- t3.start();
- }
- }
- class SyncThread implements Runnable {
- private Object obj1;
- private Object obj2;
- public SyncThread(Object o1, Object o2) {
- this.obj1 = o1;
- this.obj2 = o2;
- }
- public void run() {
- String name = Thread.currentThread().getName();
- System.out.println(name + " 1111 " + obj1);
- synchronized (obj1) {
- System.out.println(name + " 2222 " + obj1);
- work();
- System.out.println(name + " 3333 " + obj2);
- synchronized (obj2) {
- System.out.println(name + " 4444 " + obj2);
- work();
- }
- System.out.println(name + " released lock on " + obj2);
- }
- System.out.println(name + " released lock on " + obj1);
- System.out.println(name + " finished execution.");
- }
- private void work() {
- try {
- Thread.sleep(30000);
- } catch (InterruptedException e) {
- e.printStackTrace();
- }
- }
- }
复制代码- t1 1111 java.lang.Object@7943f708
- t1 2222 java.lang.Object@7943f708
- t2 1111 java.lang.Object@51733472
- t2 2222 java.lang.Object@51733472
- t3 1111 java.lang.Object@c01b05e
- t3 2222 java.lang.Object@c01b05e
- t1 3333 java.lang.Object@51733472
- t2 3333 java.lang.Object@c01b05e
复制代码 谁能帮我分析下过程
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