学完二维数组和循环后做的一道题:

根据输入的圆的半径,在控制台打印出用"*"组成的圆.
希望大家能给出更好的程序

[Java] 纯文本查看 复制代码

import java.util.Scanner;

public class Circle2 {
	//定义一个字符串类型的二维数组来存储圆形
		public static String[][] circle;
		public static int radius;
		public static void main(String[] args){
			while(true){
				System.out.println("请输入需要打印的圆的半径：");
				Scanner sc = new Scanner(System.in);
				radius = sc.nextInt();
				if(radius > 20){
					System.out.println("超出范围了！！！");
					break;
				}
				String[][] circle = new String[(radius << 1) + 1][radius << 2];
				init(circle);
				initCircle(circle);
				printCircle(circle);
			}
		}

		public static void init(String[][] circle){
			for(int i = 0; i < circle.length; i++){
				for(int j = 0; j < circle[i].length; j++){
					circle[i][j] = " ";
				}	
			}
		}
		public static void printCircle(String[][] circle){
			for(int i = 0; i < circle.length; i++){
				for(int j = 0; j < circle[i].length; j++){
					System.out.print(circle[i][j]);
				}
				System.out.println();
			}

		}
		public static void initCircle(String[][] circle){
			for(int i = 0; i < circle.length; i++){
				double angle = Math.acos((radius * 1.0 - i) / (radius + 0.1));
				int point1_y = (int)(1 + (radius << 1) - Math.sin(angle) * (radius << 1));
				int point1_x = i;
				int point2_y = circle[0].length - point1_y;
				int point2_x = i;
				circle[point1_x][point1_y] = "*";
				circle[point2_x][point2_y] = "*";
			}
		}

}

不错不错,这样可以锻炼编程思维!