/**
* Math.pow(Dluble a, Double b) 的实现
*
* @param a
* the base.
* @param b
* the exponent.
* */
public static Double getPow(double num, int n) {
Double result = 1.0;
if (n < 0) {
for (int i = n; i < 0; i++)
result /= num;
} else if (n == 0) {
return 1.0;
} else {
for (int i = 0; i < n; i++)
result *= num;
}
return result;
} |
|