PHP解析url并得到url中的参数，这是常用实例,以下进行源码分享。怎么能够把URL参数编程数组？怎么又能将 URL参数变成字符串？希望对PHP自学者有用！
<?php
$url = 'http://www.baidu.com/index.php?m=content&c=index&a=lists&catid=6&area=0&author=0&h=0®ion=0&s=1&page=1';
$arr = parse_url($url);
var_dump($arr);
$arr_query = convertUrlQuery($arr['query']);
var_dump($arr_query);
var_dump(getUrlQuery($arr_query));
/**
* 将字符串参数变为数组
* @param $query
* @return array array (size=10)
'm' => string 'content' (length=7)
'c' => string 'index' (length=5)
'a' => string 'lists' (length=5)
'catid' => string '6' (length=1)
'area' => string '0' (length=1)
'author' => string '0' (length=1)
'h' => string '0' (length=1)
'region' => string '0' (length=1)
's' => string '1' (length=1)
'page' => string '1' (length=1)
*/
function convertUrlQuery($query)
{
$queryParts = explode('&', $query);
$params = array();
foreach ($queryParts as $param) {
$item = explode('=', $param);
$params[$item[0]] = $item[1];
}
return $params;
}
/**
* 将参数变为字符串
* @param $array_query
* @return string string 'm=content&c=index&a=lists&catid=6&area=0&author=0&h=0®ion=0&s=1&page=1' (length=73)
*/
function getUrlQuery($array_query)
{
$tmp = array();
foreach($array_query as $k=>$param)
{
$tmp[] = $k.'='.$param;
}
$params = implode('&',$tmp);
return $params;
} |
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