[论坛提问] 聊天程序的一点小疑问

lwj123

今天看着毕老师的视频写了一个聊天程序，但是有一点疑问，希望能有人给解答，非常感谢！
发送端数据封装的时候，怎么才能写才能是动态的接收端端口号码，不用每当接收端端口号码改一次，发送端就得改一次程序？

import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.net.DatagramPacket;
import java.net.DatagramSocket;
import java.net.InetAddress;
import java.net.SocketException;
/**
* 聊天程序
*
* @author Administrator
*
*/
public class UdpChatDemo {
public static void main(String[] args) {
DatagramSocket sendSocket = null;
DatagramSocket recoSocket = null;
try {
sendSocket = new DatagramSocket();
recoSocket = new DatagramSocket(10000);
} catch (SocketException e) {
e.printStackTrace();
}
new Thread(new Send(sendSocket)).start();
new Thread(new Reco(recoSocket)).start();
}
}
//发送端
class Send implements Runnable {
private DatagramSocket ds;
public Send(DatagramSocket ds) {
this.ds = ds;
}
public void run(){
try{
//键盘输入流
BufferedReader bfw = new BufferedReader(new InputStreamReader(System.in));
String line = null;
while((line = bfw.readLine()) != null){
//数组缓冲区
byte[] buf = line.getBytes();
//发送端数据封装包
DatagramPacket dp = new DatagramPacket(buf,buf.length,InetAddress.getByName(""),10000);
//发送数据
ds.send(dp);
//如果发送“baibai”,则退出
if("baibai".equals(line))
break;
}
}catch(Exception e){
e.printStackTrace();
}
}
}
//接收端
class Reco implements Runnable {
private DatagramSocket ds;
public Reco(DatagramSocket ds) {
this.ds = ds;
}
public void run(){
try{
while(true){
byte[] buf = new byte[1024];
DatagramPacket dp = new DatagramPacket(buf,buf.length);
ds.receive(dp);
//解析数据包
String ip = dp.getAddress().getHostAddress();
String data = new String(dp.getData(),0,dp.getLength());
System.out.println(ip + "::" + data);
//如果对方发送baibai，则证明对方离开聊天室了
if("baibai".equals(data))
{
System.out.println(ip + "离开了聊天室！");
break;
}
}
}catch(Exception e){
e.printStackTrace();
}
}
}

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[论坛提问] 聊天程序的一点小疑问

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