多线程之送快递案例,重点重点,

[Java] 纯文本查看 复制代码

package com.heima.test;

public class Test02 {

	/**
	 * 飞毛腿快递公司有1000件快递,现在有两个员工(张三,李四)同时送快递,送一件快递需要5ms,一个快递能赚0.5员
	 * 问,他们分别送了多少件快递,分别赚了多少钱
	 * 注意:一个员工只能输出一个
	 */
	public static void main(String[] args) {
		// TODO Auto-generated method stub
		FeiMaoTui fmt = new FeiMaoTui();
		Thread t1 = new Thread(fmt);
		Thread t2 = new Thread(fmt);
		t1.setName("张三");
		t2.setName("李四");
		t1.start();
		t2.start();
	}

}

class FeiMaoTui implements Runnable {
	private int kuaijian = 1000;
	int sum =0;
	int count = 0;
	@Override
	public void run() {
		while (true) {
			synchronized (this) {
				if (kuaijian <= 0) {
					break;
				}
				try {
					Thread.sleep(5);
				} catch (InterruptedException e) {
					e.printStackTrace();
				}
				
				if ("张三".equals(Thread.currentThread().getName())) {
					sum = sum +1;
					kuaijian = kuaijian -1 ;
				}else if ("李四".equals(Thread.currentThread().getName())) {
					count = count +1;
					kuaijian = kuaijian -1 ;
				}
			}
		}
		synchronized (this) {
			if (("张三".equals(Thread.currentThread().getName()))) {
				System.out.println(Thread.currentThread().getName() + "...送了" + sum + "件快递,工赚了" + (sum * 0.5) + "元");
			}else if (("李四".equals(Thread.currentThread().getName()))) {
				System.out.println(Thread.currentThread().getName() + "...送了" + count + "件快递,工赚了" + (count * 0.5) + "元");
			}
		}
		
	}
	
}

不错的案例

谢谢楼主分享

点招机试题也可以这样放上去？？？{:2_34:}

果断收藏

还没到多线程，不过还是会