[论坛提问] 炸金花案例

尛子

import java.util.Random;
class CardTest{
public static void main(String[] args){
      FaPaiJi fpj = new FaPaiJi();
      Card c0 = fpj.getCard();
      Card c1 = fpj.getCard();
      Card c2 = fpj.getCard();
      Card[] cards = new Card[3];
      cards[0] = c0;
      cards[1] = c1;
      cards[2] = c2;
      for( int x=0; x<cards.length; x++){
         System.out.println(cards[x].getHuase()+""+cards[x].getDianshu()+"");
      }
}
}
class Card {
         //成员变量
String huase;//花色
int dianshu;//点数
         //构造方法
Card(){}
Card(String huase, int dianshu){
      this.huase = huase;
      this.dianshu = dianshu;
}
public String getHuase(){
      return huase;
}
public int getDianshu(){
      return dianshu;
}
}
class FaPaiJi {
//          成员方法
//          返回值类型
//          参数列表
public Card getCard(){
            //创建对象
   String[] hs = {"黑桃","梅花","方块","红桃"};
      Random r = new Random();
      int x = r.nextInt(4);
      String huase = hs[x];
      Card card = new Card(huase,dianshu);
      return card;
}
}
输出结果可能出现相同项，怎样解决这个问题？

/*
生成牌的时候，直接生成52不一样的牌
随机 Random().nextInt(52),返回的是 0--51
只要随机数不一样
*/
      Random r = new Random();
      int x1 = r.nextInt(13)+1;
      int x2 = r.nextInt(13)+14;
      int x3 = r.nextInt(13)+27;
      int x4 = r.nextInt(13)+40;
      String[][] hs = {"黑桃","梅花","方块","红桃"};
后面怎么做？求解

helloxiaoyu · helloxiaoyu

使用集合

import java.util.ArrayList;
import java.util.Collections;

public class D {
public static void main(String[] args) {
ArrayList<String> array = new ArrayList<String>();
// 定义一个花色数组
String[] colors = { "♠", "♥", "♣", "♦" };
// 定义一个点数数组
String[] numbers = { "A", "2", "3", "4", "5", "6", "7", "8", "9", "10","J", "Q", "K" };
for (String color : colors) {
for (String number : numbers) {
array.add(color.concat(number));
}
}
// 洗牌
Collections.shuffle(array);
for (int i = 0; i < 3; i++) {
System.out.println(array.get(i));
}
}
}

龙哥Longer · 龙哥Longer

谢谢分享，学习了

helloxiaoyu · helloxiaoyu

import java.util.Random;

public class C {

public static void main(String[] args) {
Random random = new Random();
int a[] = new int[4];
for (int i = 0; i < a.length; i++) {
//生成一个介于1到52的数字
a[i] = random.nextInt(52)+1;
for (int j = 1; j < i; j++) {
//如果重复，退回去重新生成随机数
while (a[i] == a[j]) {
i--;
}
}
}

for (int i = 1; i < a.length; i++) {
if (a[i]<14&&a[i]>0) {
System.out.println("红桃"+a[i] +"  ");
}else if (a[i]<27&&a[i]>13) {
System.out.println("方块"+(a[i]-13) +"  ");
}else if (a[i]<40&&a[i]>26) {
System.out.println("黑桃"+(a[i]-26) +"  ");
}else {
System.out.println("梅花"+(a[i]-39) +"  ");
}
}

}

}

helloxiaoyu · helloxiaoyu

import java.util.HashSet;
import java.util.Random;

public class B {
public static void main(String[] args) {

//创建一个Set集合
HashSet<Integer> hs = new HashSet<Integer>();

//向hashset中不停的存放随机数，当该集合的长度大于3就不再放了
while(hs.size()<3) {
//生成随机数
int randomNumber = new Random().nextInt(52)+1;
hs.add(randomNumber);
if (randomNumber<14&&randomNumber>0) {
               System.out.println("红桃"+randomNumber +"  ");
}else if (randomNumber<27&&randomNumber>13) {
               System.out.println("方块"+(randomNumber-13) +"  ");
}else if (randomNumber<40&&randomNumber>26) {
               System.out.println("黑桃"+(randomNumber-26) +"  ");
}else {
               System.out.println("梅花"+(randomNumber-39) +"  ");
}
}
System.out.println(hs);
}
}

流水王朝 · 流水王朝

嘿，这么巧，我昨天刚做了个炸金花小程序，我感觉最关键还是现实中抽一张牌就不会再抽出来了，但是计算机会出现重复的牌，需要判断再抽牌，若是重复就让他继续随机抽。下面是我的小程序：欢迎交流指正！
import java.util.Random;
class PukeArray1
{
public static void main(String[] args) {
//为了保证不重复并且好判断，就使用二维数组，方法比较笨点
  String[][] puke = {{"A","2","3","4","5","6","7","8","9","10","J","Q","K"},
                           {"A","2","3","4","5","6","7","8","9","10","J","Q","K"},
                           {"A","2","3","4","5","6","7","8","9","10","J","Q","K"},
                           {"A","2","3","4","5","6","7","8","9","10","J","Q","K"}};
for(int x=0;x<10;x++){
  Random ra = new Random();
  int hua1 = ra.nextInt(4);
  int shu1 = ra.nextInt(13); //此处，一维数组的索引应该由0-12；
  int hua2 = ra.nextInt(4);
  int shu2 = ra.nextInt(13);
  int hua3 = ra.nextInt(4);
  int shu3 = ra.nextInt(13);
  while((hua1*100+shu1)==(hua2*100+shu2)|(hua1*100+shu1)==(hua3*100+shu3)| (hua2*100+shu2)==(hua3*100+shu3))//判断有没有完全相同的牌。用"|"判断，有一个相等就不行，因为
  {          //现在乘积都完全保证不会有重复，一旦有一个重复，一定是完全一样。
hua1 = ra.nextInt(4);
shu1 = ra.nextInt(13);
hua2 = ra.nextInt(4);
shu2 = ra.nextInt(13);
hua3 = ra.nextInt(4);
shu3 = ra.nextInt(13);
  }
  getType(hua1);
  System.out.print(puke[hua1][shu1]+" ");
  getType(hua2);
  System.out.print(puke[hua2][shu2]+" ");
  getType(hua3);
  System.out.print(puke[hua3][shu3]+" ");
  System.out.println();

}

}

public static void getType(int x)//随机花色。
{
  switch(x)
  {
case 0:
System.out.print("红桃");
break;
case 1:
System.out.print("方块");
break;
case 2:
System.out.print("梅花");
break;
case 3:
System.out.print("黑桃");
break;
default:
System.out.println("错误花色");
break;
  }
}
}

MengYa · MengYa

赞!!!!!!!!!!!!!!!!!!!!!!!!!!!!

vipsong · vipsong

发牌可以使用模运算，如果3个人，扑克总数与3取模, 结果为0，1，2

不想睡 · 不想睡

赞!!!!!!!!!!!!!!!!!!!!!!!!!!!!

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[论坛提问] 炸金花案例

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