[自学提问] 为什么添加了"&"和"|"运算后,结果都不正确?

代码如下:
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>计算器</title>
</head>
<body>
<?php
if(!empty($_POST)) {
$Num1 = $_POST["data1"];
$Num2 = $_POST["data2"];
$yunsuan = $_POST["yunsuanfu"];
   if ($yunsuan == "+") {
        $jieguo = $Num1 + $Num2;
   } else if ($yunsuan == "-") {
        $jieguo = $Num1 - $Num2;
   }else if($yunsuan == "*") {
        $jieguo = $Num1 * $Num2;
   }else if ($yunsuan == "/") {
        $jieguo = $Num1 / $Num2;
}else if ($yunsuan == "&"){
   $jieguo = $Num1 & $Num2;
}else if($yunsuan == "|"){
   $jieguo = $Num1 | $Num2;
}

}else {
   $Num1="";
   $Num2="";
   $jieguo="";
   $yunsuan="";
}

?>
<form action="" method="post">
   <input type="text" name="data1" value="<?php echo "$Num1"; ?>" />
   <select name="yunsuanfu" >
         <option value="+" <?php if ($yunsuan=="+") {
         echo 'selected="selected"';
         } ?>>+</option>
         <option value="-" <?php if ($yunsuan=="-") {
         echo 'selected="selected"';
         } ?>>-</option>
         <option value="*" <?php if ($yunsuan=="*") {
         echo 'selected="selected"';
         } ?>>*</option>
         <option value="/" <?php if ($yunsuan=="/") {
         echo 'selected="selected"';
         } ?>>/</option>
         <option value="&" <?php if ($yunsuan=="&") {
         echo 'selected="selected"';
         } ?>>&</option>
         <option value="|" <?php if ($yunsuan=="|") {
         echo 'selected="selected"';
         } ?>>|</option>

   </select>
   <input type="text" name="data2" value="<?php echo "$Num2"; ?>" />
   <input type="submit" value="="  />
   <input type="text"  name="result" value="<?php echo $jieguo; ?>" />
</form>
</body>
</html>

zhy0372 · zhy0372

没有发现不正确啊

zkf710 · zkf710

zhy0372 发表于 2017-2-4 23:11
没有发现不正确啊

比如用123按位与45
你用我的代码计算一下, 为什么得出来的结果是00 呢, 应该是41吧

huawei · huawei

一，123按位与45 的结果是0 ，在PHP代码中 ‘123’ & ‘45’ 结果为‘00’
二，在PHP手册中是这样描述的：If both operands for the &, | and ^ operators are strings, then the operation will be performed on the ASCII values of the characters that make up the strings and the result will be a string. In all other cases, both operands will be converted to integers and the result will be an integer. （字符串与字符串的结果是字符串，整型与整型的结果是整型）
三，解决方法：修改代码 $jieguo = $Num1 & $Num2; 为 $jieguo = (int)$Num1 & (int)$Num2; 即可。

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[自学提问] 为什么添加了"&"和"|"运算后,结果都不正确?

3 个回复

交际达人