[Java] 纯文本查看 复制代码

import javax.swing.JOptionPane;

public class Circle {

	int[][] numArray;
	int record = 1;// 记录每层的起始数字
	int stepF = 0;// 每层的起始下标
	int stepE = 0;// 每层的终止下标
	int reduce = 0;// 用于记录减小量

	public static void main(String args[]) {

		new Circle().process();

	}

	public void setNum(int num) {// 递归的为二维数组赋值
		if (num > 0) {// 只要层数是正数继续赋值

			for (int i = stepF; i < stepE; i++) {// 为每层的第一列和最后一列赋值
				numArray[i][stepF] = record;
				numArray[i][stepE - 1] = record + 3 * (num - 1) - 2 * reduce;
				reduce++;
				record++;
			}
			reduce = 1;
			for (int i = stepF + 1; i < stepE - 1; i++) {// 为每层的第一行和最后一行赋值
				numArray[stepE - 1][i] = record;
				numArray[stepF][i] = record + 3 * (num - 1) - 2 * reduce;
				reduce++;
				record++;
			}
			reduce = 0;
			stepF++;
			record = record + 2 * (num - 1);// 得到下一层的起始量
			stepE--;
			setNum(num - 2);// 每递归一次每层边上的数字量减小2
		} else// 当边数含有的数字量非正时退出递归
			return;
	}

	public void process() {// 将数组中的数字按行列的形式输出
		String s = JOptionPane.showInputDialog("输入正方形矩阵的变长：");
		int num = Integer.parseInt(s);
		numArray = new int[num][num];
		String space = "";
		stepE = num;
		setNum(num);
		for (int i = 0; i < num; i++) {
			for (int j = 0; j < num; j++) {
				if (numArray[i][j] < 10 && j > 0) {// 保证输出是个正方形，不会因为是一位数或者2位数影响效果
					space = " ";
				} else
					space = " ";
				System.out.print(numArray[i][j] + space);
			}
			System.out.println();// 输入完一行后要换行
		}
	}

}

赞一个，这个我想了很久